.getCssProperty() Suggest edits
Since: 3.0.0Retrieve the value of a CSS property for a given DOM element.
For more info on working with DOM elements in Nightwatch, refer to the Finding & interacting with DOM Elements guide page.
Usage
browser.element(selector).getCssProperty(name)
Example
export default {
demoTest({ element }) {
element('#main ul li a.first')
.getCssProperty('display')
.assert.valueEquals('block');
},
async demoTestAsync({ element }) {
const result = await element('#main ul li a.first').getCssProperty('display');
console.log('display', result);
}
}
export default {
demoTest(browser: NightwatchAPI): void {
browser.element('#main ul li a.first').getCssProperty('display')
.assert.valueEquals('block');
},
async demoTestAsync(browser: NightwatchAPI): Promise<void> {
const result = await browser.element('#main ul li a.first').getCssProperty('display');
console.log('display', result);
}
}
Parameters
Name | Type | description |
---|---|---|
cssProperty |
string | The CSS property to inspect. |
Returns
Type | description |
---|---|
ScopedValue<string> | The container with a value of the css property |